CAT 2020 Slot 2 QA Q7 Inequalities & Modulus

Question 7 of the Quantitative Ability (QA) section, CAT 2020 Slot 2, with CAT's official answer.

If x and y are positive real numbers satisfying x + y = 102, then the minimum possible value of 2601(1 + \(\frac{1}{x}\))(1 + \(\frac{1}{y}\)) is

TITA: type in the answer. There are no options and no negative marking.

Answer: 2704 Inequalities & Modulus TITA

A worked solution for this question is being written. Meanwhile, practise it in a timed mock and see how other aspirants did.

Same concept in other years

See every question on AM–GM bound on a sum of reciprocal-type terms.

More Inequalities & Modulus questions from CAT

All 49 Inequalities & Modulus questions asked since 2017.