CAT 2025 Slot 2 QA Q12 Time & Work

Question 12 of the Quantitative Ability (QA) section, CAT 2025 Slot 2, with CAT's official answer and a worked solution.

Ankita is twice as efficient as Bipin, while Bipin is twice as efficient as Chandan. All three of them start together on a job, and Bipin leaves the job after 20 days. If the job got completed in 60 days, the number of days needed by Chandan to complete the job alone, is

TITA: type in the answer. There are no options and no negative marking.

Answer: 340 Time & Work TITA

Solution

  1. Efficiencies: Chandan 1, Bipin 2, Ankita 4 units/day.
  2. First 20 days all three: \(7 \times 20 = 140\). Remaining 40 days A and C: \(5 \times 40 = 200\).
  3. Total work \(= 340\) units; Chandan alone needs \(340\) days.

Same concept in other years

See every question on Work completed in phases as workers join, leave or slow down.

More Time & Work questions from CAT

All 34 Time & Work questions asked since 2017.