CAT 2023 Slot 1 QA Q18 Geometry
Question 18 of the Quantitative Ability (QA) section, CAT 2023 Slot 1, with CAT's official answer and a worked solution.
A quadrilateral ABCD is inscribed in a circle such that AB : CD = 2 : 1 and BC : AD = 5 : 4. If AC and BD intersect at the point E, then AE : CE equals
- A1 : 2
- B5 : 8
- C8 : 5
- D2 : 1
Answer: (C) 8 : 5 Geometry MCQ
Solution
- In a cyclic quadrilateral, \(\triangle AEB \sim \triangle DEC\): \(\frac{AE}{DE} = \frac{AB}{DC} = 2\).
- Also \(\triangle AED \sim \triangle BEC\): \(\frac{DE}{CE} = \frac{AD}{BC} = \frac45\).
- \(\frac{AE}{CE} = \frac{AE}{DE}\cdot\frac{DE}{CE} = 2\times\frac45 = \frac85\).
Shortcut. For a cyclic quadrilateral, \(\frac{AE}{CE} = \frac{AB\cdot AD}{CB\cdot CD} = \frac{2\cdot4}{5\cdot1}\).