CAT 2023 Slot 1 DILR Set 4 Q16–Q20
A DILR caselet from the Data Interpretation & Logical Reasoning (DILR) section of CAT 2023 Slot 1, with 5 questions (Grids & Matrices). Answers are CAT's official key.
The set
This set relies on a figure in the original paper, which is not reproduced here. The questions and answers are below.
The schematic diagram below shows 12 rectangular houses in a housing complex. House numbers are mentioned in the rectangles representing the houses. The houses are located in six columns – Column-A through Column-F, and two rows – Row-1 and Row-2. The houses are divided into two blocks - Block XX and Block YY. The diagram also shows two roads, one passing in front of the houses in Row-2 and another between the two blocks.
[Figure in the original paper]
Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).
The following information is also known.
1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
[Figure in the original paper]
Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).
The following information is also known.
1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Question 16
How many houses are vacant in Block XX?
TITA: type in the answer. There are no options and no negative marking.
Answer: 3 Grids & Matrices TITA
Solution
- Road adjacency: Row-2 houses 1 (C2, D2: 2), C1 and D1: 1, other Row-1 houses 0. The YY minimum of 15 in column E: E2 would need neighbour count 0, forcing both D1 and F1 occupied (two in Row-1 of YY), impossible. So E1 has the parking, base 12, neighbour count 1.
- If D1 were the occupied Row-1 house of YY, F2 would be occupied and vacant F1 would quote \(10+3 = 13 < 15\). So F1 and D2 are occupied, D1 vacant. In XX a quote of 24 needs base 10, road 1, neighbours 3: only B2 vacant with A2, C2, B1 occupied; then A1, C1 are vacant.
- Block XX: A2, B1, C2 occupied; A1, B2, C1 vacant, i.e. 3 vacant houses.
Question 17
Which of the following houses are definitely occupied?**
- AF2 and A2
- BD2 and B2
- CD2 and B1
- DA1 and D2
Answer: (C) D2 and B1 Grids & Matrices MCQ
Solution
- Road adjacency: Row-2 houses 1 (C2, D2: 2), C1 and D1: 1, other Row-1 houses 0. The YY minimum of 15 in column E: E2 would need neighbour count 0, forcing both D1 and F1 occupied (two in Row-1 of YY), impossible. So E1 has the parking, base 12, neighbour count 1.
- If D1 were the occupied Row-1 house of YY, F2 would be occupied and vacant F1 would quote \(10+3 = 13 < 15\). So F1 and D2 are occupied, D1 vacant. In XX a quote of 24 needs base 10, road 1, neighbours 3: only B2 vacant with A2, C2, B1 occupied; then A1, C1 are vacant.
- Definitely occupied: A2, B1, C2, D2, F1. F2 may or may not be occupied.
- Of the options, only D2 and B1 are both certain.
Question 18
Which of the following options best describes the number of vacant houses in Row-2?
- AEither 3 or 4
- BEither 2 or 3
- CExactly 3
- DExactly 2
Answer: (B) Either 2 or 3 Grids & Matrices MCQ
Solution
- Road adjacency: Row-2 houses 1 (C2, D2: 2), C1 and D1: 1, other Row-1 houses 0. The YY minimum of 15 in column E: E2 would need neighbour count 0, forcing both D1 and F1 occupied (two in Row-1 of YY), impossible. So E1 has the parking, base 12, neighbour count 1.
- If D1 were the occupied Row-1 house of YY, F2 would be occupied and vacant F1 would quote \(10+3 = 13 < 15\). So F1 and D2 are occupied, D1 vacant. In XX a quote of 24 needs base 10, road 1, neighbours 3: only B2 vacant with A2, C2, B1 occupied; then A1, C1 are vacant.
- Row-2: A2, C2, D2 occupied; B2, E2 vacant; F2 undetermined.
- So Row-2 has 2 or 3 vacant houses.
Question 19
What is the maximum possible quoted price (in lakhs of Rs.) for a vacant house in Column-E?
TITA: type in the answer. There are no options and no negative marking.
Answer: 21 Grids & Matrices TITA
Solution
- Road adjacency: Row-2 houses 1 (C2, D2: 2), C1 and D1: 1, other Row-1 houses 0. The YY minimum of 15 in column E: E2 would need neighbour count 0, forcing both D1 and F1 occupied (two in Row-1 of YY), impossible. So E1 has the parking, base 12, neighbour count 1.
- If D1 were the occupied Row-1 house of YY, F2 would be occupied and vacant F1 would quote \(10+3 = 13 < 15\). So F1 and D2 are occupied, D1 vacant. In XX a quote of 24 needs base 10, road 1, neighbours 3: only B2 vacant with A2, C2, B1 occupied; then A1, C1 are vacant.
- E1's quote is fixed at 15. E2 has no parking (YY's only one is E1): \(10 + 5\times1 + 3\times n\).
- Its neighbours D2 (occupied) and F2 (occupied in the best case) give \(n = 2\): \(10 + 5 + 6 = 21\).
Question 20
Which house in Block YY has parking space?
- AF2
- BF1
- CE2
- DE1
Answer: (D) E1 Grids & Matrices MCQ
Solution
- Road adjacency: Row-2 houses 1 (C2, D2: 2), C1 and D1: 1, other Row-1 houses 0. The YY minimum of 15 in column E: E2 would need neighbour count 0, forcing both D1 and F1 occupied (two in Row-1 of YY), impossible. So E1 has the parking, base 12, neighbour count 1.
- E1 with base 12 and one occupied neighbour is the only way to quote 15 in column E, so E1 has YY's only parking space.